Please solve above problems.
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csa=264, 2πrh=264,πrh=132,volume=924,πr^2h=924,r(πrh)=924,r(132)=924,r=7m,2πrh=264,2×22/7×7×h=264,h=6m
laba46:
Already done. Try first one (109).
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Hello Mate!
109. So, circumference of inner circle = 2πr = 440
r = 440 × 7/22 × 1/2
= 70 m
Circumference of outer circle = 506 m
R = 506 × 7/22 × 1/2
R = 23 × 7 × 1/2
R = 80.5 m
So, area if race track = πR² - πr²
= π( R² - r² )
= π( R + r )( R - r )
= 22/7 ( 80.5 + 70 )( 80.5 - 70 )
= 22/7 × 150.5 × 10.5
= 4966.5 m²
Cost of carpeting = 4966.5 × Rs 20
= Rs 99,330
Hence option (C) is correct.
110. Curved surface area of cylinder = 2πrh = 264 m²
264 / 2 = πrh
132 = πrh
Volume of cylinder = πr²h = 924 m³
πrh × r = 924 m³
132 × r = 924
r = 7 m
So, πrh = 132
22/7 × 7 × h = 132
Height = 132 / 22 = 6 m
Hence option (C) is correct.
Have great future ahead!
109. So, circumference of inner circle = 2πr = 440
r = 440 × 7/22 × 1/2
= 70 m
Circumference of outer circle = 506 m
R = 506 × 7/22 × 1/2
R = 23 × 7 × 1/2
R = 80.5 m
So, area if race track = πR² - πr²
= π( R² - r² )
= π( R + r )( R - r )
= 22/7 ( 80.5 + 70 )( 80.5 - 70 )
= 22/7 × 150.5 × 10.5
= 4966.5 m²
Cost of carpeting = 4966.5 × Rs 20
= Rs 99,330
Hence option (C) is correct.
110. Curved surface area of cylinder = 2πrh = 264 m²
264 / 2 = πrh
132 = πrh
Volume of cylinder = πr²h = 924 m³
πrh × r = 924 m³
132 × r = 924
r = 7 m
So, πrh = 132
22/7 × 7 × h = 132
Height = 132 / 22 = 6 m
Hence option (C) is correct.
Have great future ahead!
Thanks a lot dada.Where from you?
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