Question

Please solve above the ABOVE QUESTIONS

Answer 1

$\huge\underline\mathfrak{Answer}$

$\frac{1 + sec \: \: a}{sec \: \: a} = 1 + \ \frac{ \frac{1}{cos \: a} }{ \frac{1}{cos \: \: \: a} } \\ \: \\ \\ \frac{cos \: \: a \: + 1}{ \frac{cos \: \: a}{ \frac{1}{cos \: \: a \: } } } \\ \\ \frac{cos \: \: a + 1}{cos \: \: a} \times \frac{1 - cos \: \: a}{1 - cos \: \: a} \\ \\ \\ \\ \frac{1 - {cos}^{2 } a}{ \: 1 - cos {}^{2}a } \\ \\ \: using \: identity \: = \geqslant (a + b)(a - b) = \\ {a}^{2} - {b}^{2} \\ \\ \frac{sin {}^{2}a }{1 - cos {}^{}a }$

$\huge\boxed{Hense\: proved}$ ....

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