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Factorisation
a. Let x+y be z
A/Q 2z^2-9z-5 (middle term factorisation)
2z^2-10z+z-5
2z(z-5)+1(z-5)
(z-5)(2z+1)
substitute values of z as x and y
(x+y-5)(2x+2y+1) (ans)
b. let x^2+x be y then proceed
y^2+4y-12
=y^2-6y+2y-12
=y(y-6)+2(y-6)
=(y-6)(y+2)
(x^2+x-6)(x^2+x+2)
a. Let x+y be z
A/Q 2z^2-9z-5 (middle term factorisation)
2z^2-10z+z-5
2z(z-5)+1(z-5)
(z-5)(2z+1)
substitute values of z as x and y
(x+y-5)(2x+2y+1) (ans)
b. let x^2+x be y then proceed
y^2+4y-12
=y^2-6y+2y-12
=y(y-6)+2(y-6)
=(y-6)(y+2)
(x^2+x-6)(x^2+x+2)
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