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Answered by
3
answer no.1,is in attachment
Attachments:
I want all.
by this way you can solve all questions,just look at the method,and solve remaining
3 and 5
is not same
method is same,for unique solution lines intersect at one point,for infinite many solutions lines are overlapping,for no solution lines are parallel to each other
in 2 and 5 from the same method draw two lines and third line as axis mentioned,dram the triangle and write the vertex,from graph
Answered by
1
Heya !!!
__________________________
1)
The given system of equations :
5x − 6y + 30 = 0 ....(1)
5x + 4y − 20 = 0 .....(2)
Consider (1) ,
When x = 0; y = 5
When x = −6, y = 0
Consider (2),
When x = 0; y = 5
When x = 4, y = 0
GRAPH :
(prefer pic)
From the graph, we see that both the lines intersect at (0,5), so the solution of the given system of equations is :
x = 0; y = 5
Now, vertices of the ∆ formed by the above 2 lines and x−axis are :(−6,0); (4,0); (0,5)
●●●●●●●●●●●●●●●●●●
__________________________
1)
The given system of equations :
5x − 6y + 30 = 0 ....(1)
5x + 4y − 20 = 0 .....(2)
Consider (1) ,
When x = 0; y = 5
When x = −6, y = 0
Consider (2),
When x = 0; y = 5
When x = 4, y = 0
GRAPH :
(prefer pic)
From the graph, we see that both the lines intersect at (0,5), so the solution of the given system of equations is :
x = 0; y = 5
Now, vertices of the ∆ formed by the above 2 lines and x−axis are :(−6,0); (4,0); (0,5)
●●●●●●●●●●●●●●●●●●
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