Question

please solve all questions class 10 exercise 8.2​

Answer 1

Answer:

Step-by-step explanation:

Plzz tell me which question do u want

Answer 2

2. (i) 2tan30°/1+tan^2 30°

=2×1/√3 /1+(1/√3)^2

=2/√3 /1+1/3

=2/√3 /4/3

=2/√3×3/4

=3/2√3×√3/√3

=3√3/2×3

=√3/2 = sin60° (a)

(ii) 1-tan^2 45°/1+tan^2 45°

=1-(1)^2 /1+(1)^2

=1-1/1+1

=0/2 = 0 (d)

(iii) sin2A = 2sinA

sin2×0 = 2sin0

0 = 0 (a)

(iv) 2tan30°/1-tan^2 30°

=2×(1/√3) / 1-(1/√3)^2

=2/√3 / 1-1/3

=2/√3 / 2/3

=2/√3 × 3/2

=3/√3×√3/√3

=3√3/3

=√3 = tan60° (c)

3. tan(A+B) = √3 , 0°

tan(A-B) = 1/√3 , A-B=90°

A+B = 60° ___________(i)

A-B = 30° ___________(ii)

from eq (i) and (ii),

2A = 90°

A = 45°

from eq (i),

A+B = 60°

45°+B = 60°

B = 60° - 45°

B = 15°