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Answer:
1. (x+5) (x+2)
2. (x+5) (2x+5)
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Step-by-step explanation:
a ) Given quadratic polynomial x2 + 7x + 10
Using factorisation (splitting the middle term)
x2 + 7x + 10 = 0
x2 + (5x + 2x) + 10 = 0
x2 + 5x + 2x + 10 = 0
x(x + 5) + 2 (x + 5) = 0
(x + 5) (x + 2) = 0
Hence, zeroes of a given quadratic polynomial are – 5 and – 2.
Sum of zeroes = -2+(-5) = -2-5
= -7/1 = -x coefficient /x² coefficient
Product of zeroes = (-2)(-5)
= 10/1 = constant/x² coefficient
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