Math, asked by naveenasri19404, 5 hours ago

Please solve all the answers​

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Answered by kk9204694968
0

Answer:

1. (x+5) (x+2)

2. (x+5) (2x+5)

Answered by kabirjsingh27
1

Step-by-step explanation:

a ) Given quadratic polynomial x2 + 7x + 10

Using factorisation (splitting the middle term)

x2 + 7x + 10 = 0

x2 + (5x + 2x) + 10 = 0

x2 + 5x + 2x + 10 = 0

x(x + 5) + 2 (x + 5) = 0

(x + 5) (x + 2) = 0

Hence, zeroes of a given quadratic polynomial are – 5 and – 2.

Sum of zeroes = -2+(-5) = -2-5

= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)

= 10/1 = constant/x² coefficient

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