Math, asked by Anonymous, 9 months ago

Please solve all the one markers along with explanation (if needed) ​

Attachments:

Answers

Answered by MsPRENCY
3

\huge\underline\green {\tt Answers:}

\textbf {\underline {\underline {Ans :1}}} 》 0.x + 4y + 0 = 1

\textbf {\underline {\underline {Ans : 2}}}

\red {Given,}

x = a ; y = \dfrac {a}{3}

y = 3x

Then,

\dfrac {a}{3}\: is\:not\: equal\:to\: {3}a

\textbf{\underline{\underline {Solution:3}}}

we know that,

the equation of line which is parallel to x - axis is y=k

Line passes through ( 3, 7 ) coordinates.

x = 3 ; y = 7

Hence, The equation is => y = 7

\textbf {\underline {\underline{Solution:4}}}

3x - 4y = k

Put the values

we get,

3 (2) - 4 ( 1 ) = k

➡ 6 - 4 = k

➡ 2 = k

Or

K = 2

\textbf {\underline {\underline{Solution:5}}}

Given,

Graph cuts the y axis at x = 0

4y - 2x + 7 = 0

➡ 4y - 2 ( 0 ) + 7 = 0

➡ 4y - 0 + 7 = 2

➡ 4y = - 7

➡ y =  \dfrac {-7}{4}

Therefore,

The point where the graph of the linear equation cuts the y axis is : ( 0, -7/4)

\textbf {\underline {\underline {Solution :6}}}

x = k

\pink {Explanation:}

In this equation, y coordination isobviously zero ( 0 ). So, the point of the y axis won't become y = 0. Clearly, the equation will lie on the x axis. By joining the points, the straight line will be formed in the x axis only.

\huge\mathscr\blue {Be\: Brainly!!!}

Similar questions