Please solve all the one markers along with explanation (if needed)
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》 0.x + 4y + 0 = 1
》
x = a ; y =
y = 3x
Then,
we know that,
the equation of line which is parallel to x - axis is y=k
Line passes through ( 3, 7 ) coordinates.
x = 3 ; y = 7
Hence, The equation is => y = 7
3x - 4y = k
Put the values
we get,
3 (2) - 4 ( 1 ) = k
➡ 6 - 4 = k
➡ 2 = k
Or
K = 2
Given,
Graph cuts the y axis at x = 0
4y - 2x + 7 = 0
➡ 4y - 2 ( 0 ) + 7 = 0
➡ 4y - 0 + 7 = 2
➡ 4y = - 7
➡ y =
Therefore,
The point where the graph of the linear equation cuts the y axis is : ( 0, -7/4)
x = k
In this equation, y coordination isobviously zero ( 0 ). So, the point of the y axis won't become y = 0. Clearly, the equation will lie on the x axis. By joining the points, the straight line will be formed in the x axis only.
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