Question

please solve all the parts​

Answer 1

Step-by-step explanation:

Solution :-

i) Given that

y²-yz -5y+5z

=> y(y-z) -5(y-z)

=> (y-z) (y-5)

y²-yz -5y+5z = (y-z) (y-5)

ii) Given that

5p²-8pq-10p+16q

=> 5p²-10p-8pq+16q

=> 5p(p-2)-8q(p-2)

=> (p-2)(5p-8q)

5p²-8pq-10p+16q = (p-2)(5p-8q)

iii) Given that

x³-3x²+x-3

=> x²(x-3)+1(x-3)

=> (x-3)(x²+1)

x³-3x²+x-3 = (x-3)(x²+1)

iv) Given that

3ax-6ay-8by+4bx

=> 3ax+4bx -6ay-8by

=> x(3a+4b)-2y(3a+4b)

=> (3a+4b)(x-2y)

3ax-6ay-8by+4bx = (3a+4b)(x-2y)

v) Given that

y²-xy(1-x)-x³

=> y²-xy+x²y-x³

=> y(y-x)+x²(y-x)

=> (y-x)(x²+y)

y²-xy(1-x)-x³ = (y-x)(x²+y)

vi) Given that

2a-4b-xa+2bx

=> 2a-xa-4b+2bx

=> a(2-x) -2b(2-x)

=> (2-x)(a-2b)

2a-4b-xa+2bx = (2-x)(a-2b)

Answer 2

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SORRY FOR BEING LATE BUT,,

HERE ARE THE ANSWERS..☑

$(1.) {y}^{2} - yz - 5y + 5z \\ y(y - z) - 5( - y + z) \\ y(y - z) - 5(y - z) \\ (y - z)(y - 5) \: \: \: \: \: ans...$

$(2.)5 {p}^{2} - 8pq - 10p + 16q \\ p(5p-8q) -2(-5p+8q) \\ p(5p-8q) -2(5p-8q) \\ (5p-8q) (p-2) \: \: \: ans..$

$(3.) {x}^{3} - {3x}^{2} + x - 3 \\ {x}^{2} (x - 3) + 1(x - 3) \\ (x - 3)( {x}^{2} + 1) \: \: \: ans..$

$(4.)3ax - 6ay - 8by + 4bx \\ 3ax - 6ay + 4bx - 8by \\ 3a(x - 2y) + 4b(x - 2y) \\ (x - 2y)(3a + 4b) \: \: \: ans..$

$(5.) {y}^{2} - xy(1 - x) - {x}^{3} \\ {y}^{2} - xy + {x}^{2} y - {x}^{3} \\ y(y - x) + {x}^{2} (y - x) \\ (y - x)(y + {x}^{2} ) \: \: \: ans..$

$(6.)2a - 4b - xa + 2bx \\ 2(a - 2b) - x( - a + 2b) \\ 2(a - 2b) - x(a - 2b) \\ (a - 2b)(2 - x) \: \: \: ans...$

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HOPE IT HELPS YOU MY DEAR (ㆁᴗㆁ✿)

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