Question

please solve all the questions

Answer 1

HEY FRIEND

HERE IS YOUR ANSWER

GIVEN :

tanA=1

tan45°=1

So, A=45°

tanB=√3

tan60°=√3

So, B=60°

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WE GET :

A=45°
B=60°

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TO PROVE :

cosAcosB-sinAsinB=(1-√3)/2√2

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PROOF :

LHS:

=cosAcosB-sinAsinB

=cos45°cos60°-sin45°sin60°

=(1/√2)×(1/2)-(1/√2)×(√3/2)

=(1/2√2)-(√3/2√2)

=(1-√3) / 2√2

=RHS

HENCE PROVED

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HOPE THIS HELPS YOU ☺