Question

please solve all the questions it is compulsory , I will mark you as brainlist.

Answer 1

Hello sister,

You want the solutions of Q2 and Q10 I suppose because they are circled questions.
I am answering the same.

Q2. √3 = 1.732 and √2 = 1.414
To find:
$\frac{1}{ \sqrt{2} - \sqrt{3} }$

First of all we need to rationalise the above term,
$\frac{1}{ \sqrt{2} - \sqrt{3} } \times \frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \\ \frac{ \sqrt{2} + \sqrt{3} }{ {( \sqrt{2}) }^{2} - ( { \sqrt{3} )}^{2} } \\ \frac{ \sqrt{2} + \sqrt{3} }{2 - 3} \\ \frac{ \sqrt{2} + \sqrt{3} }{ - 1} \\ - ( \sqrt{2} + \sqrt{3} )$
Now we can put the value provided to us.
$- (1.414 + 1.732) \\ - 3.146$

Q10. √10 = 3.162
To find:
$\frac{1}{ \sqrt{10} }$
Again first we have to rationalise the above term.
$\frac{1}{ \sqrt{10} } \times \frac{ \sqrt{10} }{ \sqrt{10} } \\ \frac{ \sqrt{10} }{10}$
Now we should put the value provided to us.

$\frac{ \sqrt{10} }{10} = \frac{3.162}{10} \\ \frac{ \sqrt{10} }{10} = 0.3162$

Hope it helps! :)