please solve all these questions
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siddhartharao77:
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1. Work done = loss in KE = 1/2 m (v² - u²) = 1/2 * 0.050*(200²-50²) J
W = 375*5/2 J
2. Work done = 1/2 m (v² - u²)
W = 1/2 * 0.100 *[(432*5/18)²-(144*5/18)²] J
a = (v - u)/ t = [432 *5/18 - 144*5/18) /0.01 m/s²
Force F = m a
Force * thickness = W / s => s = W/ma
Or, thickness s = (v+u)/2*t = (432*5/18 + 144*5/18)/2 * 0.01 meters
3. m = total mass = 50 kg. Height h = 100 m. time t = 300 sec.
g = 10 m/s²
Work = Increase in PE = m g h = 50*10*100 = 50 kJ
Power = W/t = 500/3 Watts
4. KE = 1/2*96* 20² J = 19200 J
PE = KE on touching ground = m g h = 50*10*h
So 500 h = 19200 => h = 38.4 m
5. m = 0.5 kg. Stone falls h = 1 m downwards. g = 10 m/s².
KE gained = PE lost = m g h = 0.5 * 10 * 1 = 5 J
PE at 2 m height = m g h = 0.5 * 10 * 2 = 10 J
6. Energy spent by engine in 5 sec, = m g h + 1/2 m v²
E = 40* 10*50 + 1/2 *40*5² J
t = 5 sec.
Power = E/t = Watts/
W = 375*5/2 J
2. Work done = 1/2 m (v² - u²)
W = 1/2 * 0.100 *[(432*5/18)²-(144*5/18)²] J
a = (v - u)/ t = [432 *5/18 - 144*5/18) /0.01 m/s²
Force F = m a
Force * thickness = W / s => s = W/ma
Or, thickness s = (v+u)/2*t = (432*5/18 + 144*5/18)/2 * 0.01 meters
3. m = total mass = 50 kg. Height h = 100 m. time t = 300 sec.
g = 10 m/s²
Work = Increase in PE = m g h = 50*10*100 = 50 kJ
Power = W/t = 500/3 Watts
4. KE = 1/2*96* 20² J = 19200 J
PE = KE on touching ground = m g h = 50*10*h
So 500 h = 19200 => h = 38.4 m
5. m = 0.5 kg. Stone falls h = 1 m downwards. g = 10 m/s².
KE gained = PE lost = m g h = 0.5 * 10 * 1 = 5 J
PE at 2 m height = m g h = 0.5 * 10 * 2 = 10 J
6. Energy spent by engine in 5 sec, = m g h + 1/2 m v²
E = 40* 10*50 + 1/2 *40*5² J
t = 5 sec.
Power = E/t = Watts/
:-)
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