Question

please solve all three questions in detail and answer fast its very urgent

Answer 1

(c)
1st side=x²y-4
2nd side =3-2x²y
let 3rd side be A
perimeter of triangle=x²y+10

As we know,
perimeter of triangle= 1st side+2nd side +3rd side

x²y+10 =x²y-4 + 3-2x²y+ A
x²y+10 - x²y-4 -3-2x²y =A
x²y- x²y -2x²y +10-4-3=A
-2x²y+10-7 =A
-2x²y+ 3 =A

therefore, A= 3rd side= -2x²y+3 Ans