Question

please solve and answer it​

Answer 1

${( \frac{11}{9}) }^{3} \times { (\frac{11}{9}) }^{6} = { (\frac{11}{9}) }^{2x - 1}$

${( \frac{11}{9}) }^{3 + 6} = { (\frac{11}{9}) }^{2x - 1}$

${ (\frac{11}{9}) }^{9} = {( \frac{11}{9}) }^{2x - 1}$

Since bases are same, powers should be equal,

$9 = 2x - 1$

$10 = 2x$

$\frac{10}{2} = x$

$5 = x$