please solve and answer please
Answers
Answer:
Here, g is acceleration due to gravity
gm unit of mass in CGS unit.
kg is kilogram, unit of mass in SI unit
T1 is the tension on the string connecting A and B
T2 is the tension on the string connecting B and C
a is the acceleration of the system.
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Now write the equation of motion for the three masses.
for mass C,
(0.5 kg)g−T
2
=0.5 kg(a)
0.5g−T
2
=0.5a ------------------------------------(1)
for mass B,
T
2
−(0.1 kg)g(sin(30
∘
))−T
1
=0.1 kg(a)
T
2
−0.1g(sin(30
∘
))−T
1
=0.1a -----------------(2)
for mass A,
T1 --- (0.05 kg)g=0.05 kg(a)
T1−0.05g=0.05a --------------------------------(3)
Now, add equation (3) and (2).
T
2
−0.05g−0.1g(sin(30
∘
))=0.1a+0.05a
T
2
−0.05g−0.1g(sin(30
∘
))=0.15a ------------(4)
Now add equation (4) and (1).
0.5g−0.05g−0.1g(sin(30
∘
))=0.15a+0.5a
0.5g−0.05g−0.1g(sin(30
∘
))=0.65a
a=
0.65
0.5g−0.05g−0.1g(sin(30∘))
a=6.03 m/s
2 ))
so, the acceleration of 500 gm mass is a=6.03 m/s
2 in the downward direction.
This is your answer
Hope this helps
Explanation:
