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10ml of a solution of Nacl containing kcl on evaporation 0.93of the mixed salt which gave 1.865g of AgCl by reacting with AgNO3.Calculate the quantity of NaCl in 10ml of solution....
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NaCl + AgNO3 -----> NaNO3 + AgCl
Mol. wt of AgCl = 108+35.5=143.5
Mol. wt of NaCl = 23+35.5=58.5
143.5 g of AgCl is produced when 58.5 g of NaCl reacts
1.865 g of AgCl is produced when 58.5/143.5 * 1.865 =0.76 g of NaCl reacts
Ans. 0.76g of NaCl
Mol. wt of AgCl = 108+35.5=143.5
Mol. wt of NaCl = 23+35.5=58.5
143.5 g of AgCl is produced when 58.5 g of NaCl reacts
1.865 g of AgCl is produced when 58.5/143.5 * 1.865 =0.76 g of NaCl reacts
Ans. 0.76g of NaCl
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