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angle Did the right answer.
Muskansinha:
sorry angle D is the right answer
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Draw the required diagram
InΔABC,∠A+∠B+∠C=180°⇒∠B+∠C=180°-∠A
1/2(∠B+∠C)=90°-∠A/2⇒1/2∠B+1/2∠C=90°-∠A/2⇒∠DBC+∠DCB=90°-∠A/2
In ΔBDC,
∠BDC+∠DBC+∠DCB=180°⇒∠BDC+90°-∠A/2=180°⇒∠BDC=180°-90°+∠A/2=90°+∠A/2
∠BDC-∠A/2=90°+∠A/2-∠A/2=90°(ans.)
InΔABC,∠A+∠B+∠C=180°⇒∠B+∠C=180°-∠A
1/2(∠B+∠C)=90°-∠A/2⇒1/2∠B+1/2∠C=90°-∠A/2⇒∠DBC+∠DCB=90°-∠A/2
In ΔBDC,
∠BDC+∠DBC+∠DCB=180°⇒∠BDC+90°-∠A/2=180°⇒∠BDC=180°-90°+∠A/2=90°+∠A/2
∠BDC-∠A/2=90°+∠A/2-∠A/2=90°(ans.)
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