Question

Please solve and explain

Answer 1

Hello!

• sec 41° = $\dfrac{\sf 1}{\sf cos\:41^{\circ}}$ = $\dfrac{\sf 1}{\sf sin\:49^{\circ}}$

• cosec 41° = $\dfrac{\sf 1}{\sf sin\:41^{\circ}}$ = $\dfrac{\sf 1}{\sf cos\:49^{\circ}}$

Then,

$\dfrac{\sf 1}{\sf sin\:49^{\circ}} \sf \:x\: sin\: 49^{\circ} + cos\:49^{\circ} \sf \:x\: \dfrac{\sf 1}{\sf cos\: 49^{\circ}}$

⇒ 1 + 1 = $\boxed{\sf 2}$

Cheers!