Question

Please solve and explain example one

Answer 1

let PQRS is a rectangle in which PR and QS be the diagonals,

now

In ∆ PQR and ∆ SQR,

PQ=RS (opposite sides of the rectangle),

QR=QR (common),

PR=QS (since diagonals are equal in rectangle),

therefore by SSS congruence rule,

both the ∆'s are congruent,

hence

angle Q = angle R (By CPCT),


angle P = angle R (opposite angles of //gm are equal),

angel Q + angle R =180° (since PS parallel to QR),

angle Q + angle Q =180°,


2 × angle Q =180°,

then

angle Q=180°/2,

angle Q=90°,

then

angle Q = angle R = angle P = angle S =90°

Answer 2

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