Question

please solve and explain this

Answer 1

Heya....!!!

HERE IS YOUR ANSWER

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Given, radius of wire = diameter/2
= 0.5/2 = 0.25mm = 0.25*10^-3m
p = 1.6*10^-8 roh-m
R = 10roh

1) We know that, resistance,
R = pl/A = pl=πr^2
So l = Rπr^2/p
= 10*3.14*0.25*0.25*10^-6/1.6*10^-8
= 122.66m

2) Resistance, R is inversely proportional to d^2.
So if diameter is doubled, then resistance become one fourth of its original value.

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HOPE IT HELPS!!!

Answer 2

hii dear________________

good afternoon_________________

_______here is your answer____________

R = pl/a, where,

R= Resistance of the wire

p= specific resistance

l=length of the wire

A= area of cross section of the wire

With the given values,

A= 1.96349541*10^-7

p = 1.6*10^-8

R= 10

l=(10*1.96349541*10^-7) /(1.6*10^-8)

l=122.7m