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HERE IS YOUR ANSWER:
We are given that AB II CD and /_ EGC =120°
NOW Angle EGC = angle GHA = 120° (since these both angles are forming corresponding angles)
Therefore, angle GHB + angle GHA = 180°(linear pair)
So, angle GHB + 120° = 180°
Angle GHB = 180° - 120°
Angle GHB = 60°
HOPE IT HELPS YOU.
PLZ MARK THIS ANSWER AS BRAINLIEST.
We are given that AB II CD and /_ EGC =120°
NOW Angle EGC = angle GHA = 120° (since these both angles are forming corresponding angles)
Therefore, angle GHB + angle GHA = 180°(linear pair)
So, angle GHB + 120° = 180°
Angle GHB = 180° - 120°
Angle GHB = 60°
HOPE IT HELPS YOU.
PLZ MARK THIS ANSWER AS BRAINLIEST.
harjotsingh213pbec17:
60 degree
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Can’t understand the handwriting
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