please solve and send a picture of this question
Answers
Answer:
the device which has a power of 11 watt is likely to burn first.
Explanation:
It is because , these 2 devices are connected to a mains which is of 440v and such a huge amount is entering both the devices.
since,we know that when an huge amount of current enters in a circuit, then the fuse wire gets melted and finally burn.
so, in the above case the device having 44watt which is more than the device having 11 watt. And hence, the fuse of the device having lower i.e 11 watt gets burn as a result of overloading.
hope it will be useful 2 u.
plzzzz mark as brainliest.
Answer:
The fuse of device of rating 11W; 220V will burn.
R = V2/W
∴ Resistance of 11W device will be four times then that of the device of 44w.
∴ Voltage across 11W = 352 V
∴ Voltage across 44W = 88 V
352V across the device of 11W ; 220V rating is sufficient to burn the fuse of the device