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Clearly, we have :
B-3=E...(i)
B + 3 = D ... (ii) A + B = D + E + 10 ...(iii)
B=C+2...(iv) A+B+C+D+E=133...(v)
From (i) and (ii), we have 2 B=D+E...( vi) From (iii) and (vi), we have: A = B + 10 ...(vii) Using (iv), (vi) and (vii) in (v), we get: (B + 10) + B + (B - 2) + 2B = 133 ⇒ 5B = 125 B = 25.
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