Question

please solve and send me the solution of your copy

Answer 1

Answer:

(x^a/x^b)^1/ab*(x^b/x^c)^1/bc*(x^c/x^a)^1/ac

={x^(a-b)}^1/ab*{x^(b-c)^1/bc}{x^(c-a)^1/ac}

=x^(a-b)/ab*x^(b-c)/bc*x^(c-a)/ac

=x^{(a-b)/ab+(b-c)/bc+(c-a)/ac}

=x^{(a-b).c+(b-c).a+(c-a).b}/abc

=x^(ac-bc+ab-ac+bc-ab)/abc}

=x^(0/abc)

=x^0

=1