Question

please solve and send mee ​

Answer 1

Answer:

Given is to evaluate, $\frac{[(\frac{1}{3}^-^2 )-(\frac{1}{4} )^-^3] }{(\frac{1}{4} )^-^2}$

          $\frac{[(\frac{1}{3}^-^2 )-(\frac{1}{4} )^-^3] }{(\frac{1}{4} )^-^2} = \frac{9-64}{16}$

          $\frac{9-64}{16} =\frac{-55}{16}$

We know that,

   $\left[\begin{array}{ccc}(\frac{1}{3}) ^-^2 = \frac{1^-^2}{3^-^2} = \frac{1}{9^-^1} = 9\\(\frac{1}{4}) ^-^3 = \frac{1^-^3}{4^-^3} = \frac{1}{64^-^1} = 64 \\ (\frac{1}{4}) ^-^2 = \frac{1^-^2}{4^-^2} = \frac{1}{16^-^1} = 16\end{array}\right]$

                     Hope it helps you ^_^