Question

Please solve and send the solution of the attachment
Don't give direct answer
Answer will be given brainliest

Answer 1

a^2+b^2=(a-b)^2+2ab
=(√5-1/√5+1_√5+1/√5-1)^2+2×1
=(√5-1)^2-(√5+1)^2/6 +2
=5+1-2√5-5-1-2√5/6. +2
=4√5/6 +2
=4√5+12/6=4(√5+3)/6=2(√5+3)/3
is your answer

Answer 2

⇒ $( \frac{ \sqrt{5} -2}{ \sqrt{5} + 2 } )^2 + ( \frac{ \sqrt{5} +2 }{ \sqrt{5} -2 } )^2$

By Factorization,


⇒ $(\frac{ \sqrt{5} -2 }{ \sqrt{5} + 2 }$×$\frac{ \sqrt{5} - 2 }{ \sqrt{2} - 2 } )^2$ + $( \frac{ \sqrt{5} + 2 }{ \sqrt{5} - 2 }$×$\frac{ \sqrt{5} + 2 }{ \sqrt{5} + 2 } )^2$



⇒ $( \frac{( \sqrt{5} - 2)^2}{( \sqrt{5})^2 - (2)^2 } )^2 + ( \frac{( \sqrt{5} + 2)^2 }{( \sqrt{5} )^2 - (2)^2} )^2$



⇒ $( \frac{ 5 +2 -4 \sqrt{5} }{5 - 4 })^2 + ( \frac{5 + 2 + 4\sqrt{5} }{5 - 4} )^2$

⇒ $( \frac{7 - 4 \sqrt{5} }{1})^2 + ( \frac{7 + 4 \sqrt{5} }{ 1 } )^2$

⇒ ( 7 - 4√5)² + (7 + 4√5)²

⇒ 49 + 80 - 56√5 + 49 + 80 + 56√5 

⇒ 129 + 129 

⇒ 258








i hope this will help you



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