Question

please solve answer 16 points​

Answer 1

SOLUTION

Let the three numbers be a-d,a,a+d.

Their sum is -3 [given]

Then,

(a-d)+a+(a+d)= -3

=)3a= -3

=) a= -3/3

=) a= -1

And their product is 8 [given]

=)(a-d)a(a+d)= a(a²-d²)= 8

=)-1(-1²-d²)=8

=)-1(1-d²)=8

=)-1+d²= 8

=) d²= 1+8

=) d²= 9

=) d²= (3)²

=) d= ±3

Hope it helps ☺️

Answer 2

Step-by-step explanation:

Let the three numbers are:

(a-d),a,(a+d)

By first condition,

a-d+a+a+d=-3

3a=-3

a=-1

By second condition,

a-d×a×a+d=8

a cube -a d square=8

(-1) cube-(-1) d square-1=8

-1+d square=8

d square=8+1

d square=9

so,d=3 or -3

but -3 does not satisfy the given conditions

Hence,

The difference is 3.

I hope it helps.....