Question

please solve. answer is (x-2) (x+2+y)

Answer 1

Here is the answer..

$x {}^{2} - 2y + xy - 4 \\ = x {}^{2} + xy - 2y - 4 \\ = x(x +y ) - 2(y + 2 )$
$\therefore (x - 2)(x + y + 2)$

Hence ,

Final Answer =>

$\texttt{(x - 2)(x + y + 2)}$

Answer 2

QUESTION......

SOLVE IT :- ${x}^{2} -2y + xy - 4$

SOLUTION........
This could be solved with the process of factorisation ;

${x}^{2} -2y + xy - 4$

= ${x}^{2} + xy- 2y - 4$

HERE WE HAVE MAKE PAIR OF TERMS :-

1ST PAIR ARE :-
${x}^{2} + xy$

2ND PAIR IS :-
$2y - 4$

NOW NEXT STEP IS TO FIND COMMON IN BOTH THE PAIRS .

In ,

i) ${x}^{2} + xy$ "x" is common .

ii) $2y - 4$ "2" is common.

So,

${x}^{2} + xy- 2y - 4$

= $x(x+y) - 2(y+2) = [tex] (x-2) (x+y+2)$

AS "y" IS TAKEN COMMON IT IS TAKEN AS SINGLE.

ANSWER IS :-

$(x-2) (x+y+2).$

BE BRAINLY!!!