please solve Anwer =1 question no 19
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Step-by-step explanation:
tan(A+B)=√3 THEN A+B =tan^-1(√3)=60 degrees
A+B=60------> 1
sin(A-B)=1/2=>A-B=sin^-1(1/2)
A-B=30-------->2
Solving 1 and 2 we get 2A=90
A=45 and substituting this in 1 we'll get B=15
in the question they asked tan(2A-2B)
tan(2(45)-2(15)) = tan(90-30) =tan(60)=√3
therefore tan (2A-2B)=√3
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