Question

please solve as fast as you can​

Answer 1

Answer:

xsinA = ycosA.

▶⏩To prove:-)

=> x² + y² = 1.

▶⏩ xsin³A + ycos³A = sinAcosA.

↪➡ (xsinA) sin²A + (ycosA) cos²A = sinAcosA.

↪➡ (xsinA) sin²A + (xsinA) cos²A = sinAcosA. [ ycosA = xsinA].

↪➡ (xsinA) (sin²A + cos²A) = sinAcosA.

↪➡ xsinA = sinAcosA...........(1).

[ Sin²A + Cos²A = 1 ].

↪➡ x = cosA

[ Squaring both side ].

↪➡ x² = cos²A ...................(2).

▶⏩ Now,

↪➡ xsinA = ycosA.

↪➡ cosAsinA = ycosA.......[ From equal(1)].

↪➡ y = sinA.

[ Squaring both side ].

↪➡ y² = sin²A ...................(3).

▶⏩ Add in equation (2) and (3).

↪➡ x² + y² = sin²A + cos²A.

↪➡ x² + y² = 1.✔✔

✴✴ Hence, it is proved ✅✅.

Answer 2

Answer:

$</p><p>{\green{\underline{\underline{\huge{\mathfrak\pink{your\:answer\:attached\:in\:the\:photo}}}}}}$