Question

please solve as soon as possible​

Answer 1

Answer:

Pythagoras theorem states that

${(ab)}^{2} = {(ca)}^{2} + {(cb)}^{2}$

${ \sqrt{3} }^{2} = { \sqrt{2} }^{2} + {y}^{2}$

$3 = 2 + {y}^{2}$

${y}^{2} = 3 - 2 = 1$

$y = \sqrt{1}$

$length \: of \: ca = 1cm$

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Step-by-step explanation:

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