Question

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Answer 1

Question :

Q1) Find the perimeter of each of the following figure :

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Given:

(1) $\green{\bf{Sides}} \begin{cases} \sf{AB=27cm} \\ \sf{BC=35cm} \\ \sf{CD=45cm} \\ \sf{AD=35cm} \end{cases}$

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To find :

➡ Perimeter of the figure =?

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Solution :

First consider the sides ABCD in the figure :

$\implies \sf \: perimeter = sum \: of \: all \: sides$

$\\ \implies\sf{Perimeter \: =sum \: of \: all \: sides}$

$\\ \implies\sf{Perimeter=AB+BC+CD+DA}$

$\\ \implies\sf{Perimeter=27+35+45+35cm}$

$\\ \implies\sf{Perimeter=62+80}$

$\\ \implies\sf{Perimeter=142cm}$

$\\ \implies\boxed{\sf{Perimeter=142cm}}$

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Given :

(2) $\green{\bf{Sides}} \: \begin{cases} \: \sf{AB=18cm } \\ \sf{BC=18cm} \\ \sf{CD=18cm} \\ \sf{AD=18cm} \end{cases}$

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To find :

➡ Perimeter of this figure =?

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Solution :

$\\ \: \implies \sf \: perimeter \: = sum \: of \: \: all \: sides$

$\\ \implies\sf{Perimeter=AB+BC+CD+DA}$

$\\ \implies\sf{Perimeter=18+18+18+18cm}$

$\\ \implies\sf{Perimeter=36+36}$

$\\ \implies\sf{Perimeter=72cm}$

$\\ \implies\boxed{\sf{Perimeter=72cm}}$

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Given:

(3)$\green{\bf{Sides}} \begin{cases} \sf {CB=4cm} \\ \sf{CD=12cm} \\ \sf{DE=12cm} \\ \sf{EF=4cm} \\ \sf{FG=16cm} \\ \sf{GA=8cm} \\ \sf{AB=16cm} \end{cases}$

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Solution :

$\\ \implies \sf \: perimeter \: = sum \: of \: all \: sides$

$\\ \implies\sf{Perimeter=(CB+CD+DE+EF)+(FG+GA+AB)}$

$\\ \implies\sf{Perimeter=(4+12+12+4)+(16+8+16)}$

$\\ \implies\sf{Perimeter=(24+8)+(32+8)}$

$\\ \implies\sf{Perimeter=(32)+(40)}$

$\\ \implies\sf{Perimete=72cm}$

$\\ \implies\boxed{\sf{Perimeter=72cm}}$