please solve as urgent as possible .. And it will be too much helpful if you attach solution's pic.
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LHS=(tanA+cosecB)²
-(cotB-secA)²
=(tan²A+cosec²B+2tanAcosecB)
-(cot²B+sec²A-2cotBsecA)
=tan²A+cosec²B+2tanAcosecB
-cot²B-sec²A+2cotBsecA)
=(tan²A-sec²A)+(cosec²B-cot²B)+2sinA/cosAsinB + 2cosB/sinBcosA
= -1 +1 + 2/(sinBcosA)[sinA+cosB]
= 2/(CosAsinB)[sinA+cosB]
=[2sinAcosB]/(cosAsinB)[(sinA+cosB)/sinAcosB]
= 2tanAcotB(secB+cosecA)
=RHS
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