Question

Please solve at the earliest

Answer 1

Answer:₹105000

Step-by-step explanation

1 st year : 15%

600,000 x15/100 = ₹90000

2nd year: 13.5%

600,000 x13.5/100 = ₹81000

3 rd year :12%

600,000 x 12/100 = ₹72000

A.P:₹ 90000,₹81000,₹72000

a =90000

d =-9000

n=10

Sn = n/2[2a+(n-1)d]

S10= 10/2 [2(90000)+(10-1) (-9000)]

S10 = 5[180000-81000]

S10 = 495000

The cost of the equipment at the 10th year is :

Initial cost - s10

600,000 -495000

= ₹ 105000