Question

Please solve big help

Answer 1

Answer:

a )

i ) 5x + 3 = 15 + x

5x - x = 15 - 3

4x = 12

x = 12 / 4

x = 3

ii ) 3a - 4 = 2 ( 4 - a )

3a - 4 = 8 - 2a

3a + 2a = 8 + 4

5a = 12

a = 12 / 5

Answer 2

★Answer :-

• $\rm A.)(i.) \;x=3\; (ii.) a=\dfrac{12}{5}$
• B.)$\rm(4x-5)(x+2)$

★Step-By-Step-Explanation :-

★$\rm A.)( i.) 5x+3=15+x$

Now the x in R.H.S will in L.H.S and will be substracted also , 3 in L.H.S will be in R.H.S also be substracted . So,

$\rm \implies 5x-x=15-3$

now we will further substract them ,

$\rm \implies 4x=12$

Now , x will remain and 4 will come in R.H.S being divided ,

$\rm \implies x=\dfrac{12}{4}$

So , value of x becomes ,

$\rm \implies \bf x =3$

$\therefore \rm Value \;of\;x\;in\;this\;case\;is\;3$

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★$\rm (ii.) 3a-4=2(4-a)$

Now in R.H.S the brackets will be removed and being multiplied

$\rm\implies 3a-4=8-2a$

Now , 2a in R.H.S will be in L.H.S will be added and -4 will be in R.H.S being added as their is negative sign in L.H.S ,

$\rm \implies 3a+2a=8+4$

Now further adding ,

$\rm \implies 5a=12$

Now , a will be there only and 5 will be divided

$\rm \implies\bf a =\dfrac{12}{5}$

$\therefore\rm Value\;of\;x\;in\;this\; case\;is\;\dfrac{12}{5}$

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★$\rm (2.) 4x^2+3x-10$

By using Middle term factorisation we will have to break the middle term

$\rm \implies 4x^2+8x-5x-10$

Now , again take common in between two

$\rm \implies 4x(x+2)-5(x+2)$

Now , just right the answer ,

$\rm \implies \bf (4x-5)(x+2)$

$\rm \therefore (4x-5)(x+2) is \;the\;answer$ .

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