please solve both sums and send
13 ans is 26 and 14 is 73
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Explanation:
let the tens digit's no. be x
so, the unit digit's no. is 3x
so, the required no. is 10*x + 1*3x
=13x
if the no. is reversed it becomes 3x * 10 + 1*x
=31x
B/P 31x = 13x + 36
or, 31x - 13x = 36
or, 18x = 36
or, x= 36/18
or, x= 2
so, x= 2
The original no. is 10*2 + 1*3*2
=20*6
=26 (ans)
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