Question

Please solve both the questions. thanks you if you did​

Answer 1

Answer:

$33)x - \frac{4}{3x} = \frac{( - 1)}{3} \\ \frac{3 {x}^{2} - 4}{3x} = \frac{( - 1)}{3} \\ Cross \: multiply \\ 3(3 {x}^{2} - 4) = ( - 1)3x \\ 9 {x}^{2} - 12 = ( - 3x) \\ 9 {x}^{2} + 3x - 12 = 0 \\ 3 {x}^{2} + x - 4 = 0 \\ 3 {x}^{2} - 3x + 4x - 4 = 0 \\ (3 {x}^{2} - 3x) + (4x - 4) = 0 \\ 3x(x - 1) + 4(x - 1) = 0 \\ (x - 1)(3x + 4) = 0 \\ (x -1 = 0)(3x + 4 = 0) \\ x = 1 \: and \: x = \frac{( - 4)}{3} \\ Therefore, \: x = 1 \\ 34)x - \frac{4}{x} = \frac{21}{5} \\ \frac{ {x}^{2} - 4 }{x} = \frac{21}{5} \\ 5( {x}^{2} - 4) = 21(x) \\ 5 {x}^{2} - 20 = 21x \\ 5 {x}^{2} - 21x - 20 = 0 \\ 5 {x}^{2} - 25x + 4x - 20 = 0 \\ (5 {x}^{2} - 25x) + (4x - 20) = 0 \\ 5x(x - 5) + 4(x - 5) = 0 \\ (x - 5)(5x + 4) = 0 \\ (x - 5 = 0)(5x + 4 = 0) \\ x = 5 \: and \: x = \frac{( - 4)}{5} \\ Therefore, \: x = 5$