Question

Please solve both this question fastly​

Answer 1

Answer:

f(-1)=(-1)^3+6×(-1)^2+11

= -1+6-11+6

= -12+12

= 0

Also,

f(-2)=(-2)^3+6(-2)^2+11(-2)

= -8+6×4-22+6

=30-30

=0

And similarly,

f(-3)=0

Therefore the integers roots of the polynomials f(x) are -1, -2, -3.

I hope this is ur answer.