Question

Please solve both with steps... Correct answer brainliest and thanks​

Answer 1

Answer:

1.( 12pq-9r)²-(9pq+4r)²

(144pq-81r)-(81pq+16r)

144pq-81r-81pq-16r

144pq-81pq-81r-16r

53pq-75r

Answer 2

Answer:

$(12pq - 9r)^2 - (9pq + 4r)^2$ $=(21pq - 5r)(3pq - 13r)$

$2^{2^3} + 2^{1^2} + 3^{2^0} + 3^{0^2}$ = 264

Step-by-step explanation:

$(12pq - 9r)^2 - (9pq + 4r)^2$

$=(12pq - 9r + 9pq + 4r)(12pq - 9r - 9pq - 4r)$  [∵ $a^2 - b^2 = (a + b)(a - b)$]

$=(21pq - 5r)(3pq - 13r)$

$2^{2^3} + 2^{1^2} + 3^{2^0} + 3^{0^2}$

$=2^{8} + 2^{2} + 3^{1} + 3^{0}$  [∵ $a^0 = 1$]

$=256 + 4 + 3 + 1$

=264