Math, asked by jaycomanthramNithin, 1 year ago

please solve brainliest friends

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jaycomanthramNithin: please write step by step answer

Answers

Answered by siddhartharao77
1
(i)

= \ \textgreater \   \sqrt{48} -  \sqrt{72} -  \sqrt{27} + 2 \sqrt{18}

= \ \textgreater \  4 \sqrt{3} - 6 \sqrt{2} -3  \sqrt{3} + 6 \sqrt{2}

= \ \textgreater \  -3 \sqrt{3} + 4 \sqrt{3}

= \ \textgreater \   \sqrt{3}



(ii)

Given : 2 \sqrt[3]{4} + 7 \sqrt[3]{32} -  \sqrt[3]{500}

= \ \textgreater \  2 \sqrt[3]{4} + 2 * 7 \sqrt[3]{4} - 5 \sqrt[3]{2^2}

= \ \textgreater \  2 \sqrt[3]{4} + 14  \sqrt[3]{4} - 5 \sqrt[3]{4}

= \ \textgreater \  11 \sqrt[3]{4}




Hope this helps!

siddhartharao77: :-)
jaycomanthramNithin: question 1 how did root 48 become 4root3
siddhartharao77: root 48 = root 16 * 3 = 4 root 3.
jaycomanthramNithin: oh thank you i did not know hhat
jaycomanthramNithin: second question why did yo multiply 2 with 3 under root of 4
siddhartharao77: I didnt muliplied anything..I have just written what is there in the question.
jaycomanthramNithin: seco nd step where did that 500 go
siddhartharao77: cube root of 500 = cube root 125 * 4 = 5 * cube root 4(2^2).
Answered by dfgh4
0
hello friends
hey your answer
plz mark the brainliest
plz follow me
dfgh ☺️☺️☺️
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jaycomanthramNithin: how did root 48 become 4root 3in second step
dfgh4: plz mark the brainliest
dfgh4: 48 =4×4×3 then common is 4. 4√3
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