please solve by elimination method
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the answer is given in the attachment
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Answer:
Given :-
EQ 1 :- 5x + 4y - 4 = 0
EQ 2 :- x - 12y - 20 = 0
Now, EQ 1 × 3
We get,
15x + 12y - 12 = 0
Now Solving I and 2
15x + 12y -12 =0
+ x - 12y - 20 = 0
_______________
16x - 32 = 0
16x = 32
=> x = 2
Now, Put x = 2 in eq 2
x - 12y - 20 = 0
(2) - 12y = 20
-12y = 18
=> y = 18/-12 = -3/2
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