Question

Please solve by steps.​

Answer 1

Answer:

The answer is $\dfrac{2z(z-2)}{z-8}$

Step-by-step explanation:

  $\dfrac{4yz(z^2+6z-16)}{2y(z^2-64)}$

Factorize numerator and denominator

$=\dfrac{4yz(z^2-2z+8z-16)}{2y(z^2-8^2)}\\\\=\dfrac{4yz(z(z-2)+8(z-2))}{2y(z+8)(z-8)}\\\\=\dfrac{4yz(z-2)(z+8)}{2y(z+8)(z-8)}$

Cancel common terms from numerator and denominator

$=\dfrac{2z(z-2)}{z-8}$