Question

please solve by using suitable identity​

Answer 1

Answer:

Step-by-step explanation:

(vii) (y-1)(y+2)=y²+2y-1y-2=y²+y-2

(viii) (z+3)(z-7)=z²-7z+3z-21=z²-4z-21

(ix) (p+8)(p-3)=p²-3p+8p-24=p²+5p-24

(x) (z+6)(z-5)=z²-5z+6z-30=z²+z-30

(xi) (x-6)(x-9)=x²-9x-6x+54=x²-15x+54

(xii) (x-10)(x+9)=x²+9x-10x-90=x²-x-90

(xiii) (y-4)(y+4)=y²-4² (from the property factorisation of the difference of two squares that is a²-b²=(a-b)(a+b) )=y²-16

(xiv) (x-4)(x-14)=x²-14x-4x+56=x²-18x+56

(xv) (x-8)(x-2)=x²-2x-8x+16=x²-10x+16