PLEASE SOLVE
Centre of mass of two thin uniform rods of same length but made up of
different materials & kept as shown , can be, if the meeting point is the origin
of co-ordinates
(A) (L/2, L/2)
(B) (2L/3, L/2)
(C)(L/3, L/3)
(D) (L/3, L/6)
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The meeting point is the origin of co-ordinates is L = (L / 3,L / 6)
Explanation:
Here let us consider the mass of rod along Y axis be m 1 and that along X axis be m 2
- Now Centre of mass of m 1 is (0, L / 2 )
- Centre of mass of m 2 is ( L / 2 ,0)
Centre of mass of combined system:
CM of system line on L.
L1 ( y − L / 2) = ( −L/2 ÷ L/2)(x−0)
y = −x + L / 2
= (L / 3,L / 6)
Thus the meeting point is the origin of co-ordinates is L = (L / 3,L / 6)
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