Question

Please solve class 10 math mtg​

Answer 1

Answer:

$</p><p>2x-y-3= 0....(1)\\ \\ \\ </p><p>4x-y-5= 0...(2)\\ \\ \\ </p><p>2x-y-3= 0\\ \\ \\ </p><p>2x-y= 3\\ \\ \\ </p><p>2x= 3+y\\ \\ \\ </p><p>x= \frac{(y+3)}{2}\\ \\ \\ </p><p>by \: putting\: value\: of\: x\: in\: equation\: 2\\ \\ \\ </p><p>4x-y-5= 0\\ \\ \\ </p><p>4x-y= 5\\ \\ \\ </p><p>4× {\frac{y+3}{2}} -y= 5\\ \\ \\ </p><p>\frac{4(y+3)}{2} -y= 5\\ \\ \\ </p><p>\frac{4y+12}{2} -y= 5\\ \\ \\ </p><p>\frac{(4y+12)-(2y)}{2} = 5\\ \\ \\ </p><p>\frac{2y+12}{2}= 5\\ \\ \\ </p><p>by\: cross\: multiplication\\ \\ \\ </p><p>2y+12= 5×2\\ \\ \\ </p><p>2y+12= 10\\ \\ \\ </p><p>2y= 10-12\\ \\ \\ </p><p>2y = -2\\ \\ \\ </p><p>y= \frac{-2}{2}\\ \\ \\ </p><p>y= -1\\ \\ \\ </p><p>by \: putting\: value\: of \: y\: in\: equation\: 2\\ \\ \\ </p><p>4x-y-5=0\\ \\ \\ </p><p>4x-(-1)-5= 0\\ \\ \\ </p><p>4x+1-5= 0\\ \\ \\ </p><p>4x-4= 0\\ \\ \\ </p><p>4x= 4\\ \\ \\ </p><p>x= \frac{4}{4}\\ \\ \\ </p><p>x= 1\\ \\ \\ </p><p>therefore\: x= 1,\: y= -1$