Question

please solve clearly​

Answer 1

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

A bag contains 15 cards bearing number 1,2,3,4....., 14, 15

So the total number of cards = 15

So the total number of possible outcomes = 15

1.

Let A be the event that the CARD DRAWN IS A PRIME NUMBER

Then the prime numbers between 1 and 15 are

2, 3, 5, 7, 11, 13

So the total number of possible outcomes for the event A is 6

So the required probability

$\displaystyle \: \sf{P(A) = \frac{6}{15} = \frac{2}{5} \: }$

2.

Let B be the event that the card drawn is DIVISIBLE BY 2

So the event points for the event B is

2, 4, 6, 8, 10, 12, 14

So the total number of possible outcomes for the event B is 7

So the required probability is

$\displaystyle \: \sf{P(B) = \frac{7}{15} \: }$