Question

please solve D ....​

Answer 1

Answer:

traingle DBC =180

angleD+angleB+angleC=180

50+30+B=180

80+B=180

B=180-80

B=100

line ABC is a straight line =180

angle X +100=180

x=180-100

x=80

angle A+ angle B+angle D=180

25+80+D=180

105+D=180

D=180-105

D=75

line BD is a straight line=180

y+75=180

y=180-75

y=105

Answer 2

Answer:

In /\ BCD , 30°+50°+ < DBC = 180° [Angle sum property]

So, <DBC=180°-(30°+50°)

=180°-80°

=100°

Now, <DBC+x°=180° [Angles in a straight line]

100°+x°=180° [<DBC=100°]

x°=180°-100°

=80°

Then , we consider the other triangle,

25°+x°+●=180° [Angle sum property]

25°+80°+●=180° [x°=80°]

●=180°-105°

●=75°

y°+●=180° [Angles in a straight line]

y°+75°=180° [●=75°]

y°=180°-75°

y°=105°

x°=80° & y°=105°