Question

please solve d) question ​

Answer 1

Answer :

$\large \sf \implies −3a^2−ab −7ac −2b^2+6bc +4c^2$

Solution :

question :

Subtract : $\sf 3a(a+b+c) -2b(a-b+c) \: from \: 4c(-a+b+c)$

To Find :

• 4c(-a+b+c) - [3a(a+b+c) -2b(a-b+c)]

Let's solve,

➠ Open the brackets by multiplying

$\sf -4ca+4bc+4c^2 - [3a^2+3ab+3ac -2ab + 2b^2+2bc] \\ \\ \sf\implies -4ac+4bc+4c^2 -3a^2 -3ab -3ac + 2ab - 2b^2 +2bc$

➠ Bring like terms together,

$\sf \implies -3a^2 - 2b^2 + 4c^2 + 2ab -3ab -4ac -3ac + 4bc +2bc$

➠ Add like terms

$\sf \implies -3a^2 - 2b^2 + 4c^2 -ab -7ac + 6bc$

Therefore,

3a(a+b+c) -2b(a-b+c) subtraced from 4c(-a+b+c) = −3a²−ab −7ac −2b² +6bc +4c²

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Answer 2

Arre vidya...aur meetings organize nhi kr rhi kya??