Math, asked by Anvi02, 1 month ago

please solve
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Answers

Answered by Varadvb2007
0

Answer:

1. root -x-2 =0

or

2. root x-2 =0

Step-by-step explanation:

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Answered by harshsharma88494
1

Answer:

0 to infinity

Step-by-step explanation:

It must be notes that most of the sqrt functions have range over non - negative reals except some cases where special functions say trig. apply. For example, sqrt(abs(sin(x))).

But as here is a non - bounded range for the function (abs(x) - 2), and sqrt(x) has range over non - negative reals,

The range for this function is the set of every real number from 0 to infinity including 0.

And here you go... Let's see the graph.

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