Question

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Answer 1

Answer:

10) -2 and 3/2

11) a = 1 , b = -3

Step-by-step explanation:

10)

$2{x}^{2} + x - 6 = 0 \\ \\ 2 {x}^{2} + 4x - 3x - 6 = 0$

$2x(x + 2) - 3(x + 2) = 0 \\ \\ (x + 2)(2x - 3) = 0$

Thus, roots of given quadratic are -2 and 3/2

11)

$sum \: of \: roots = \frac{ - b}{a } \\ \\ 1 + 2 = \frac{ - b}{a}$

$\frac{3}{1} = \frac{ - b}{a} \\ \\ b = - 3 \: \: \: \: \: a = 1$

Hope it helps

Answer 2

10) 2x² + x - 6 = 0

• 2x² + (4-3)x - 6 = 0
• 2x² + 4x - 3x - 6 = 0
• 2x(x+2) - 3(x+2) = 0
• (x+2)(2x-3) = 0
• Roots are x = -2 , ⅔