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Answer 1

Answer:

QUESTION NUMBER 14

Step-by-step explanation:

$(1 + {m}^{2} ) {x}^{2} + 2mcx + {c}^{2} - {a}^{2} = 0 \\ \\ for \: equal \: roots \\ \\ {(2mc)}^{2} - 4(1 + {m}^{2} )( {c}^{2} - {a}^{2} ) = 0 \\ \\ {m}^{2} {c}^{2} = (1 + {m}^{2} )( {c }^{2} - {a}^{2} ) \\ \\ {m}^{2} {c}^{2} = {c}^{2} - {a}^{2} + {m}^{2} {c}^{2} - {a}^{2} {m}^{2} \\ \\ {c}^{2} - {a}^{2} = {a}^{2} {m}^{2} \\ \\ {c}^{2} = {a}^{2} (1 + {m}^{2} ).$

Answer 2

Answer:

hey here is your solution in above pics

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Step-by-step explanation:

if u have any doubt in geometry or statistics

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